Answer
$16x^{2}-8xz+z^{2}$
Work Step by Step
Using the square of the binomial $(a-b)^{2}=a^{2}-2ab+b^{2}$,
$(4x-z)^{2}=(4x)^{2}-2(4x)(z)+z^{2}=16x^{2}-8xz+z^{2}$.
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