Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Chapter Test - Page 557: 22

Answer

$x = 0$

Work Step by Step

The least common denominator, or LCD, is $x + 1$. Multiply each side of the equation by $x + 1$ to eliminate the fractions: $$\begin{align*} (x+1)\cdot \frac{3x}{x+1}&=0 \cdot (x+1)\\ \\3x &= 0 \end{align*}$$ Divide each side of the equation by $3$: $$\begin{align*} \frac{3x}{3}&=\frac{0}{3}\\ x &= 0 \end{align*}$$ To check the solution, plug in $0$ for $x$ into the original equation: $$\begin{align*} \frac{3(0)}{0 + 1} &\stackrel{?}{=} 0\\ 0&\stackrel{\checkmark}{=}0 \end{align*}$$
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