Answer
$\dfrac{x + 4}{x - 3}, \space x \ne -3, 3$
Work Step by Step
Factor all expressions in the original exercise:
$\dfrac{(x + 4)(x + 3)}{(x + 3)(x - 3)}$
Cancel common factors in the numerator and denominator:
$\dfrac{x + 4}{x - 3}$
Restrictions on $x$ occur when the value of $x$ makes the denominator equal $0$, which means that the rational expression becomes undefined.
To find the restrictions, use the Zero-Product Property by equating each factor of the denominator to zero, then solve each equation for $x$.
First factor:
$\begin{align*}
x + 3 &= 0\\
x&=-3
\end{align*}$
Second factor:
$\begin{align*}
x - 3 &= 0\\
x&=3
\end{align*}$
Restriction: $x \ne -3, 3$
