Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Chapter Test - Page 557: 20

Answer

$x = 1$

Work Step by Step

The least common denominator, or LCD, is $4$. Multiply each side of the equation by $4$ to eliminate the fractions: $$\begin{align*} 4 \cdot \frac{x}{2}&=\frac{x+1}{4} \cdot 4\\ \\2x &= x + 1 \end{align*}$$ Subtract $x$ from each side of the equation: $$x = 1$$ To check the solution, plug in $1$ for $x$ into the original equation: $$\begin{align*} \frac{1}{2} &\stackrel{?}{=} \frac{1 + 1}{4}\\ \frac{1}{2}&\stackrel{?}{=}\frac{2}{4}\\ \frac{1}{2}&\stackrel{\checkmark}{=}\frac{1}{2} \end{align*}$$
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