Chapter 8 - Rational Functions - 8-1 Inverse Variation - Practice and Problem-Solving Exercises - Page 505: 45

$\text{G}$

Recall: $(a-b)^2=a^2-2ab+b^2$ Use the formula above to obtain: \begin{align*} (8-5i^2)^2&=8^2-2(8)5i)+(5i)^2\\ &=64-80i+25i^2\\ \end{align*} With $i^2=-1$< then the equation above becomes: \begin{align*} (8-5i)^2&=64-80i+25(-1)\\ &=64-80i-25\\ &=39-80i \end{align*}