## Algebra 2 Common Core

Published by Prentice Hall

# Chapter 6 - Radical Functions and Rational Exponents - Properties of Exponents: 4

#### Answer

$\dfrac{9y^6}{x^8}$

#### Work Step by Step

RECALL: (i) $(a^m)^n = a^{mn}$ (ii) $(ab)^m=a^mb^m$ (iii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Use the rules above to have: $=3^2(x^{-4})^2(y^3)^2 \\=9x^{-4(2)}y^{3(2)} \\=9x^{-8}y^6 \\=9y^6 \cdot \dfrac{1}{x^8} \\=\dfrac{9y^6}{x^8}$

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