Answer
$h$
Work Step by Step
Using the laws of exponents, the given expression, $
\left( \dfrac{1}{h^{-2}} \right)^{-1}\cdot h^3
,$ is equivalent to
\begin{align*}
&
\dfrac{1}{h^{-2(-1)}}\cdot h^3
&\text{ (use $(a^x)^y=a^{xy}$)}
\\\\&=
\dfrac{1}{h^{2}}\cdot h^3
\\\\&=
\dfrac{h^3}{h^{2}}
\\\\&=
h^{3-2}
&\text{ (use $\dfrac{a^x}{a^y}=a^{x-y}$)}
\\\\&=
h^{1}
\\&=
h
.\end{align*}
Hence, the simplified form of the given expression is $
h
$.
