Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Properties of Exponents: 13

Answer

$\dfrac{t^{12}}{r}$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne0$ (ii) $a^0=1, a\ne0$ (iii) $a^{-m} = \dfrac{1}{a^m}. a\ne0$ Use the rule above to have: $=r^{2-3}s^{4-4}t^{6-(-6)} \\=r^{-1}s^{0}t^{6+6} \\=\dfrac{1}{r} \cdot 1 \cdot t^{12} \\=\dfrac{t^{12}}{r}$
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