Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Properties of Exponents - Page 360: 14

Answer

$4x^{3}$

Work Step by Step

Multiplying the numerators and the denominators, the given expression, $ \dfrac{x^2y}{4}\cdot\dfrac{16x}{y} ,$ is equivalent to \begin{align*} \dfrac{x^2y(16x)}{4y} .\end{align*} Using the laws of exponents, the expression above is equivalent to \begin{align*}\require{cancel} & \dfrac{16x^{2+1}y}{4y} \\\\&= \dfrac{16x^{3}y}{4y} \\\\&= \dfrac{4x^{3}\cdot4y}{4y} \\\\&= \dfrac{4x^{3}\cdot\cancel{4y}}{\cancel{4y}} \\\\&= 4x^{3} .\end{align*} Hence, the simplified form of the given expression is $ 4x^{3} $.
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