Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-4 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 309: 51

Answer

a factor

Work Step by Step

Equating the given expression, $ x+1 ,$ to zero and then solving for $x,$ then \begin{align*} x+1&=0 \\ x+1-1&=0-1 \\ x&=-1 .\end{align*} Using $ -1 $ in the synthetic division below, then the remainder is $ 0 $ (bottom-right number). Since the remainder is equal to zero, then $ x+1 $ is a factor of $x^3+x^2-16x-16$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.