Answer
NOT a factor
Work Step by Step
Equating the given expression, $
x-1
,$ to zero and then solving for $x,$ then
\begin{align*}
x-1&=0
\\
x-1+1&=0+1
\\
x&=1
.\end{align*}
Using $
1
$ in the synthetic division below, then the remainder is $
-30
$ (bottom-right number).
Since the remainder is NOT zero, then $
x-1
$ is NOT a factor of $x^3+x^2-16x-16$.