Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-4 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 309: 35

Answer

$P(a)=12$

Work Step by Step

Using the synthetic division shown below, the remainder (bottom-right number) of $( x^3+7x^2+4x )\div( x+2 ),$ is \begin{align*} 12 .\end{align*} Substituting $x= -2 $ in $P(x)= x^3+7x^2+4x ,$ then by the Remainder Theorem, the remainder when $P(x)$ is divided by $ x+2 $ is \begin{align*} P(-2)&= (-2)^3+7(-2)^2+4(-2) \\&= -8+7(4)+4(-2) \\&= -8+28-8 \\&= 12 .\end{align*} The two solutions above show that the remainder, $P(a),$ is \begin{align*} P(a)=12 .\end{align*}
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