Answer
NOT a factor
Work Step by Step
Equate $x+2$ to zero then solve for $x,$:
\begin{align*}
x+2&=0
\\
x+2-2&=0-2
\\
x&=-2
.\end{align*}
Using $
-2
$ in the synthetic division below, then the remainder is $
12
$ (bottom-right number).
Since the remainder is NOT zero, then $
x+2
$ is NOT a factor of $x^3+x^2-16x-16$.
