#### Answer

$x^3-4x^2-21x=x(x-7)(x+3)$

#### Work Step by Step

Factor out the GCF $x$ to get
$\\=x(x^2-4x-21)$.
Factor the trinomial to get
$\\=x(x-7)(x+3)$.
Check by multiplying the factors:
$=x(x^2+3x-7x-21)
\\=x(x^2-4x-21)
\\=x^3-4x^2-21x$.

Published by
Prentice Hall

ISBN 10:
0133186024

ISBN 13:
978-0-13318-602-4

$x^3-4x^2-21x=x(x-7)(x+3)$

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