Answer
$x^3-4x^2-21x=x(x-7)(x+3)$
Work Step by Step
Factor out the GCF $x$ to get
$\\=x(x^2-4x-21)$.
Factor the trinomial to get
$\\=x(x-7)(x+3)$.
Check by multiplying the factors:
$=x(x^2+3x-7x-21)
\\=x(x^2-4x-21)
\\=x^3-4x^2-21x$.
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 5 - Polynomials and Polynomial Functions - 5-2 Polynomials, Linear Factors, and Zeros - Practice and Problem-Solving Exercises - Page 293: 9
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
