Answer
$x^3-7x^2-18x=x(x-9)(x+2)$
Work Step by Step
Factor out the GCF $x$ to get
$\\=x(x^2-7x-18)$.
Factor the trinomial to get
$\\=x(x-9)(x+2)$.
Check by multiplying the factors:
$=x(x^2+2x-9x-18)
\\=x(x^2-7x-18)
\\=x^3-7x^2-18x$.