## Algebra 2 Common Core

$x^3-7x^2-18x=x(x-9)(x+2)$
Factor out the GCF $x$ to get $\\=x(x^2-7x-18)$. Factor the trinomial to get $\\=x(x-9)(x+2)$. Check by multiplying the factors: $=x(x^2+2x-9x-18) \\=x(x^2-7x-18) \\=x^3-7x^2-18x$.