## Algebra 2 Common Core

First, factor the polynomial completely: $\\y=3x(x^2-1) \\y=3x(x-1)(x+1).$ Equate each unique factor to zero, then solve each equation: $3x=0 \text{ or } x-1=0 \text{ or } x+1=0 \\x=0 \text{ or } x = 1 \text{ or } x=-1.$ Thus, the zeros are -1, 0, and 1, each with multiplicity one.