## Algebra 2 Common Core

$-\frac{3}{2}$ (with multiplicity 1) and 1 (with multiplicity 2)
Equate each unique factor to zero, then solve each equation: $2x+3=0 \text{ or } x-1=0 \\x=-\frac{3}{2} \text{ or } x = 1$. The factor $x-1$ appears twice, so the zero 1 has multiplicity 2.