#### Answer

$-\frac{3}{2}$ (with multiplicity 1) and 1 (with multiplicity 2)

#### Work Step by Step

Equate each unique factor to zero, then solve each equation:
$2x+3=0 \text{ or } x-1=0
\\x=-\frac{3}{2} \text{ or } x = 1$.
The factor $x-1$ appears twice, so the zero 1 has multiplicity 2.