#### Answer

$9x^3+6x^2-3x=3x(3x-1)(x+1)$

#### Work Step by Step

Factor out the GCF $3x$ to get
$3x(3x^2+2x-1)$.
Factor the trinomial to get
$3x(3x-1)(x+1)$.
Check by multiplying the factors:
$\\3x(3x^2+3x-x-1)
\\=3x(3x^2+2x-1)
\\=9x^3+6x^2-3x.$

Published by
Prentice Hall

ISBN 10:
0133186024

ISBN 13:
978-0-13318-602-4

$9x^3+6x^2-3x=3x(3x-1)(x+1)$

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