Answer
$\left(\dfrac{19}{2}, 5\right)$
Work Step by Step
Solve by elimination in order to remove or elminiate avariable.
This can be achieved by multiplying $-1$ to the first equation to eliminate the $x$ variable:
$-1(2x-3y)=-1(4)\longrightarrow -2x+3y=-4$
Add the equations together :
$-2x+3y=-4$
$\underline{2x-5y=-6}$
$-2y=-10$
Divide both sides by $-2$ to obtain:
\begin{align*}\dfrac{-2y}{-2}&=\dfrac{-10}{-2}\\\\
y&=5\end{align*}
Plug in $y=5$ into one of the equations to find $x$:
\begin{align*}2x-3(5)&=4\\
2x-15&=4\\
2x&=19\\
x&=\frac{19}{2}
\end{align*}
The solution is $x=$$\dfrac{19}{2}$ and $y=5$ or $\left(\frac{19}{2}, 5\right)$.
