Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises - Page 147: 59

Answer

$(-7, -26)$

Work Step by Step

Solve using substitution because you can use $y=4x+2$ (the second equation) to substitute $4x+2$ to $y$ in the first equation: Hence, $3x-(4x+2)=5$ $3x-4x-2=5$ $-x-2=5$ $-x=7$ $x=-7$ Plug in $x=-7$ into the equations: \begin{align*} y&=4(-7)+2 &\text{and}& &3(-7)-y=5\\ y&=-26 &\text{and}& &y=-26 \end{align*} Thus, the solution is $x=-7$ and $y=-26$ or $(-7, -26)$.
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