## Algebra 2 Common Core

$m = 4$, $n = -3$ or $(4, -3)$
Given: $2m = -4n - 4$ $3m + 5n = -3$ Divide both sides of the first equation, $2m = -4n - 4$, by $2$: $2m \div 2 = (-4n - 4) \div 2$ $m = -2n - 2$ Substitute $m = -2n - 2$ into the second equation, $3m + 5n = -3$: $3m + 5n = -3$ $3(-2n - 2) + 5n = -3$ $-6n + 5n - 6 = -3$ $-n - 6 = -3$ Add $6$ to both sides: $-n = 3$ Divide both sides by $-1$: $n = -3$ Substitute $n = -3$ into the equation, $m = -2n - 2$ $m = -2n - 2$ $m = -2(-3) - 2$ $m = 6 - 2$ $m = 4$ $m = 4$, $n = -3$