Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-4 Area and the Law of Sines - Practice and Problem-Solving Exercises - Page 932: 7

Answer

$9.1 \text{in.}^2 $

Work Step by Step

When the two sides let's say a and b and the angle C are given, then the area $\bf{A}$ can be calculated as: $A=\dfrac{1}{2} ab \sin \text{C}$ From the given figure, we have: $ a= 10 \ \text{in.}; b = 7 \ \text{in.} ; C= 15^{\circ}$ $A=\dfrac{1}{2} (10) (7) \sin 15^{\circ} \approx 9.1 \text{in.}^2 $
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