Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-4 Area and the Law of Sines - Practice and Problem-Solving Exercises - Page 932: 10

Answer

$x \approx 9.2$

Work Step by Step

Apply the Law of Sines. $\dfrac{\sin A}{a} =\dfrac{\sin B}{b} =\dfrac{\sin C}{c} $ Rearrange the two ratio setup to obtain: $\dfrac{\sin A}{a} =\dfrac{\sin C}{c}\\\dfrac{\sin 48^{\circ}}{7.3} =\dfrac{\sin C}{x} \\ x=\dfrac{7.3 \sin C}{\sin 48^{\circ}} ~~~(1)$ Since, the sum of interior angles of a triangle is equal to $180^{\circ}$. Thus, we can write as: $A+B+C =180^{\circ} \\ 48^{\circ}+21^{\circ} +C=180^{\circ} \implies C = 111^{\circ}$ Hence, the equation (1) becomes: $x=\dfrac{7.3 \sin 111^{\circ}}{\sin 48^{\circ}} \approx 9.2$
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