Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-4 Area and the Law of Sines - Practice and Problem-Solving Exercises - Page 932: 12

Answer

$x \approx 41.1^{\circ}$

Work Step by Step

Apply the Law of Sines. $\dfrac{\sin A}{a} =\dfrac{\sin B}{b} =\dfrac{\sin C}{c} $ Rearrange the above two ratio setup to obtain: $\dfrac{\sin A}{a} =\dfrac{\sin B}{b}\\\dfrac{\sin x^{\circ}}{27} =\dfrac{\sin 43^{\circ}}{28} \\ \sin x^{\circ}=\dfrac{27 \sin 43^{\circ}}{28} $ Rearrange the equation (1) as follows: $x =\sin^{-1} (\dfrac{27 \sin 43^{\circ}}{28}) \approx 41.1^{\circ}$
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