Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-4 Area and the Law of Sines - Practice and Problem-Solving Exercises - Page 932: 14

Answer

$27^{\circ}$

Work Step by Step

Consider a triangle $\text{DEF}$. Apply the Law of Sines. $\dfrac{\sin D}{d} =\dfrac{\sin E}{e} =\dfrac{\sin F}{f} $ Rearrange the above two ratio setup to obtain: $\dfrac{\sin D}{d} =\dfrac{\sin F}{f}\\\dfrac{\sin D}{16} =\dfrac{\sin 43^{\circ}}{ 24} \\ \sin D=\dfrac{16 \sin 43^{\circ}}{24} $ In order to calculate $\angle{D}$, we need to rearrange the equation (1) as follows: $\angle{D} =\sin^{-1} (\dfrac{16 \sin 43^{\circ}}{24}) \approx 27^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.