Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-4 Area and the Law of Sines - Practice and Problem-Solving Exercises - Page 932: 13

Answer

$33.5^{\circ}$

Work Step by Step

Apply the Law of Sines. $\dfrac{\sin A}{a} =\dfrac{\sin B}{b} =\dfrac{\sin C}{c} $ Rearrange the above two ratio setup to obtain: $\dfrac{\sin B}{b} =\dfrac{\sin C}{c}\\\dfrac{\sin x^{\circ}}{10} =\dfrac{\sin 96^{\circ}}{ 18} \\ \sin x^{\circ}=\dfrac{10 \sin 96^{\circ}}{18} $ In order to calculate $x^{\circ}$, we need to rearrange the equation (1) as follows: $x^{\circ} =\sin^{-1} (\dfrac{10 \sin 96^{\circ}}{18}) \approx 33.5^{\circ}$
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