Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-2 Probability - Practice and Problem-Solving Exercises - Page 687: 51



Work Step by Step

With $24$ green marbles, $22$ blue marbles, $14$ yellow marbles, and$12$ red marbles, the total number of marbles is \begin{align*}\require{cancel} & 24+22+14+12 \\&= 72 .\end{align*} The probability of getting a green or red is given by the number of green and red marbles divided by the total number of marbles. That is \begin{align*} & \dfrac{24+12}{72} \\\\&= \dfrac{36}{72} \\\\&= \dfrac{\cancel{36}^1}{\cancel{72}^2} \\\\&= \dfrac{1}{2} .\end{align*} Hence, the probability of randomly choosing a green or red ball is $ \dfrac{1}{2} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.