## Algebra 2 Common Core

$\dfrac{1}{2}$
With $24$ green marbles, $22$ blue marbles, $14$ yellow marbles, and$12$ red marbles, the total number of marbles is \begin{align*}\require{cancel} & 24+22+14+12 \\&= 72 .\end{align*} The probability of getting a green or red is given by the number of green and red marbles divided by the total number of marbles. That is \begin{align*} & \dfrac{24+12}{72} \\\\&= \dfrac{36}{72} \\\\&= \dfrac{\cancel{36}^1}{\cancel{72}^2} \\\\&= \dfrac{1}{2} .\end{align*} Hence, the probability of randomly choosing a green or red ball is $\dfrac{1}{2} .$