Answer
Not mutually exclusive
Work Step by Step
For mutually exclusive events, $P(A\text{ or }B) = P(A) + P(B)$. We have: $$P(A) + P(B) = \frac{1}{2} + \frac{1}{3} = \frac{5}{6} \not= \frac{2}{3}.$$ $P(A\text{ or B})$ is not equal to $P(A) + P(B)$, so these are not mutually exclusive.
