Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-2 Probability - Practice and Problem-Solving Exercises - Page 687: 46

Answer

$\dfrac{25b-7a^3}{5a^2b}$

Work Step by Step

The $LCD$ in the given expression, $ \dfrac{5}{a^2b}-\dfrac{7a}{5b^2} ,$ is $ 5a^2b^2 .$ Expressing the terms to equivalent fractions that use the $LCD$ as denominator results to \begin{align*}\require{cancel} & \dfrac{5}{a^2b}\cdot\dfrac{5b}{5b}-\dfrac{7a}{5b^2}\cdot\dfrac{a^2}{a^2} \\\\&= \dfrac{25b}{5a^2b}-\dfrac{7a^3}{5a^2b^2} \\\\&= \dfrac{25b-7a^3}{5a^2b} .\end{align*} Hence, the given expression simplifies to $ \dfrac{25b-7a^3}{5a^2b} .$
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