Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-2 Probability - Practice and Problem-Solving Exercises - Page 687: 39

Answer

Choice B

Work Step by Step

In the form $x^2+bx=c,$ the given equation, $ x^2+12x+5=3 ,$ is equivalent to \begin{align*}\require{cancel} x^2+12x+5-5&=3-5 \\ x^2+12x&=-2 .\end{align*} To complete the square of the expression on the left, add $\left( \dfrac{b}{2} \right)^2$ on both sides. That is \begin{align*}\require{cancel} x^2+12x+\left( \dfrac{12}{2} \right)^2&=-2+\left( \dfrac{12}{2} \right)^2 \\\\ x^2+12x+\left( 6 \right)^2&=-2+\left( 6 \right)^2 \\ x^2+12x+36&=-2+36 \\ x^2+12x+36&=34 .\end{align*} The expression above is a perfect square trinomial since it takes the form $x^2+2ax+a^2.$ Its factored form is $(x+a)^2.$ Therefore, the equation above is equivalent to \begin{align*} (x+6)^2=34 .\end{align*} Hence, Choice B.
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