## Algebra 2 (1st Edition)

$a^{-m}=\dfrac{1}{a^m}$
As per the zero property, we have $a^0=1$ Thus, $\dfrac{1}{a^m}=\dfrac{a^0}{a^m}$ ...(1) Now, we need to use the quotient property. $\dfrac{a^0}{a^m}=a^{0-m}=a^{-m}$ Equation (1) becomes: $\dfrac{1}{a^m}=\dfrac{a^0}{a^m}=a^{-m}$ This gives: $a^{-m}=\dfrac{1}{a^m}$ Hence, the result has been verified.