Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 40


$A=\dfrac{x^2 \sqrt 3}{36}$

Work Step by Step

To calculate the area the formula is given as follows: $A=\dfrac{\sqrt 3}{4}s^2$ Length of the side of the triangle is $s=\dfrac{x}{3}$ Now, $A=\dfrac{\sqrt 3}{4}s^2=\dfrac{\sqrt 3}{4}(\dfrac{x}{3})^2$ This gives: $A=\dfrac{\sqrt 3}{4}(\dfrac{x^2}{9})=\dfrac{x^2 \sqrt 3}{36}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.