Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 41


$V=\dfrac{\pi x^3}{2}$

Work Step by Step

To calculate the volume the formula is given as follows: $V=\pi r^2 h$ Here, we have $r=x; h=\dfrac{x}{2}$ Now, $V=\pi r^2 h=\pi (x)^2 \cdot (\dfrac{x}{2})=\dfrac{\pi x^2 (x)}{2} $ This gives: $V=\dfrac{\pi x^3}{2} $
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