Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 44


$4x^{-1} y^3$

Work Step by Step

Here, we have $3 x^{3} y^{2}=\dfrac{12 x^{2} y^{5}}{a}$ Now, $a= \dfrac{12 x^{2} y^{5}}{3 x^{3} y^{2}}$ This gives: $a= 4 x^{2-3} \times y^{5-2}=4x^{-1} y^3$
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