Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 46


$(x^{12} y^{16})=(x^{6} y^{8}) \times (x^{6} y^{8}) $

Work Step by Step

Here, we have $(x^{12} y^{16})=(x^1 y^{1}) (x^{11}y^{15})$ This gives: $(x^{12} y^{16})=x^{2} y^{6} \times x^{10} y^{10}$ or, $(x^{12} y^{16})=(x^{2} y^{6}) \times (x^{10} y^{10})$ Hence, $(x^{12} y^{16})=(x^{6} y^{8}) \times (x^{6} y^{8}) $
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