Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Mixed Review - Page 830: 55


No solution as $x \ne 4$

Work Step by Step

We have $\dfrac{3x}{x-4}=\dfrac{2(x-4)}{x-4}+\dfrac{12}{x-4}$ Re-write as: $3x=2(x-4)+12$ or, $3x=2x-8+12$ or, $x =4$ and $x -4 \ne 0 \implies x \ne 4$ No solution since there is the domain restriction $x \ne 4$
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