Answer
See answer below.
Work Step by Step
The Trigonometric Identities are written as below:
$\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{-2}{2 \sqrt {10}}=-\dfrac{\sqrt {10}}{\sqrt {10}}$
$\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{6}{2 \sqrt {10}}=\dfrac{3 \sqrt {10}}{10}$
$\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{-2}{6}=-\dfrac{1}{3}$
$\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{6}{-2}=-3$
$\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{2 \sqrt {10}}{6}=\dfrac{\sqrt {10}}{3}$
$\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{2 \sqrt {10}}{-2}=-\sqrt{10}$
