## Algebra 2 (1st Edition)

$326.63^{\circ}$
Here, we have $\sin \theta =-0.55; 270^{\circ} \lt \theta \lt 360^{\circ}$ $\theta'=\sin^{-1} (-0.55) \approx -33.37^{\circ}$ This angle $\theta'$ is in the $II$ quadrant . We need to get the co-terminal angle in the range of $270^{\circ} \lt \theta \lt 360^{\circ}$. We will just have to add $360^{\circ}$. Then we have $\theta=-33.37^{\circ}+360^{\circ} \approx 326.63^{\circ}$