# Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Mixed Review - Page 830: 46

$113$

#### Work Step by Step

We have $\sqrt[3]{x+12}=5$ We need to take the cube of each side. or, $(\sqrt[3]{x+12})^3=(5)^3$ or, $x+12 =125$ $\implies x =113$

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