## Algebra 2 (1st Edition)

$x=-5$
We have $\dfrac{5}{x+1}+3=\dfrac{-7}{x+1}$ ...(1) Re-write as: $5+3x+3=-7$ or, $3x =-15 \implies x=-5$ We need to check the solution. Plug $x=-5$ into equation (1). $\dfrac{5}{-5+1}+3=\dfrac{-7}{-5+1}$ $\implies \dfrac{7}{4}= \dfrac{7}{4}$; Verified