Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Mixed Review - Page 830: 54

Answer

$x \pm 4$

Work Step by Step

We have $3x+16=x(x+3)$ ...(1) Re-write as: $3x+16=x^2+3x$ or, $x^2-16 =0 \implies (x-4)(x+4)=0$ or, $x \pm 4$ and $x \ne -3, \dfrac{-16}{3}$ The solutions are not undefined values. So, $x \pm 4$
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