## Algebra 2 (1st Edition)

$\approx 3.13 95 25 976$
From the previous part (b) we have that the perimeter of the n-sided polygon is: $P=n (2x)= 2n \sin (\dfrac{180}{n})^{\circ}$ ...(1) Also, $2n \sin (\dfrac{180}{n})^{\circ} \approx 2 \pi$ Thus, $n \sin (\dfrac{180}{n})^{\circ} \approx \pi$ Set $n=50$, then we have $(50) \sin (\dfrac{180}{50})^{\circ} \approx \pi$ Hence, $\pi \approx 3.13 95 25 976$