Answer
$\approx 3.13 95 25 976$
Work Step by Step
From the previous part (b) we have that the perimeter of the n-sided polygon is:
$P=n (2x)= 2n \sin (\dfrac{180}{n})^{\circ}$ ...(1)
Also, $ 2n \sin (\dfrac{180}{n})^{\circ} \approx 2 \pi$
Thus, $ n \sin (\dfrac{180}{n})^{\circ} \approx \pi$
Set $n=50$, then we have
$ (50) \sin (\dfrac{180}{50})^{\circ} \approx \pi$
Hence, $\pi \approx 3.13 95 25 976$
