Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Skill Practice - Page 857: 29c


$\approx 3.13 95 25 976$

Work Step by Step

From the previous part (b) we have that the perimeter of the n-sided polygon is: $P=n (2x)= 2n \sin (\dfrac{180}{n})^{\circ}$ ...(1) Also, $ 2n \sin (\dfrac{180}{n})^{\circ} \approx 2 \pi$ Thus, $ n \sin (\dfrac{180}{n})^{\circ} \approx \pi$ Set $n=50$, then we have $ (50) \sin (\dfrac{180}{50})^{\circ} \approx \pi$ Hence, $\pi \approx 3.13 95 25 976$
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