# Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Skill Practice - Page 857: 29c

$\approx 3.13 95 25 976$

#### Work Step by Step

From the previous part (b) we have that the perimeter of the n-sided polygon is: $P=n (2x)= 2n \sin (\dfrac{180}{n})^{\circ}$ ...(1) Also, $2n \sin (\dfrac{180}{n})^{\circ} \approx 2 \pi$ Thus, $n \sin (\dfrac{180}{n})^{\circ} \approx \pi$ Set $n=50$, then we have $(50) \sin (\dfrac{180}{50})^{\circ} \approx \pi$ Hence, $\pi \approx 3.13 95 25 976$

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