## Algebra 2 (1st Edition)

$2n \sin (\dfrac{180}{n})^{\circ}$
Here, $\theta=(\dfrac{1}{n}) \times 360^{\circ}=(\dfrac{360}{n})^{\circ}$ $\sin \theta/2=\dfrac{x}{1}$ This gives: $\sin \dfrac{(\dfrac{360}{n})^{\circ}}{2}=x$ $\implies x=\sin (\dfrac{180}{n})^{\circ}$ Now, the perimeter of the n-sided polygon is: $P=n (2x)= 2n \sin (\dfrac{180}{n})^{\circ}$