## Algebra 2 (1st Edition)

$a \approx 9.87 \\ b \approx 4.39\\A=66^{\circ}$
Here, $\cos B=\dfrac{a}{c}$ This gives: $\cos 24^{\circ}=\dfrac{a}{10.8} \implies a \approx 9.87$ Now, $\sin B=\dfrac{b}{c}$ This gives: $\sin 24^{\circ}=\dfrac{b}{10.8} \implies b \approx 4.39$ Since the sum of a triangle is $180^{\circ}$ and the right angle is $90^{\circ}$: $A=180^{\circ}-24^{\circ}-90^{\circ}=66^{\circ}$