Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Skill Practice - Page 857: 27


$c \approx 73$ $a \approx 65.6$ $B=26^{\circ}$

Work Step by Step

Here, $\cos A=\dfrac{b}{c}$ This gives: $\cos 64^{\circ}=\dfrac{32}{c} \implies c \approx 73$ Now, $\sin A=\dfrac{a}{c}$ This gives: $\sin 64^{\circ}=\dfrac{a}{73} \implies a \approx 65.6$ Since the sum of a triangle is $180^{\circ}$ and the right angle is $90^{\circ}$: $ B=180^{\circ}-64^{\circ}-90^{\circ}=26^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.