## Algebra 2 (1st Edition)

$a \approx 9.177$ $b \approx 13.11$ Angle B= $55^{\circ}$.
$\sin 35^{\circ}=\dfrac{Opposite}{Hypotenuse}=\dfrac{a}{16}$ This gives: $a \approx 9.177$ and $\cos 35^{\circ}=\dfrac{Adjacent}{Hypotenuse}=\dfrac{b}{16}$ This gives: $b \approx 13.11$ Since, the triangle is $180^{\circ}$ and the right angle is $90^{\circ}$: Angle A is $35^{\circ}$, thus Angle B must be $55^{\circ}$.