Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 30


See below.

Work Step by Step

Since the events are independent, $P(\text{A and B})=P(A)P(B)$, thus $P(B)=\frac{P(\text{A and B})}{P(A)}=\frac{0.2}{0.25}=0.8$
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