Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 22


See below

Work Step by Step

Given $$\frac{y^2}{100}-\frac{x^2}{49}=1$$ Rewrite as: $$\frac{y^2}{10^2}-\frac{x^2}{7^2}=1$$ Thus, we have $a=10\\b=7$
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