Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 2


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Work Step by Step

Given $$\frac{1}{2}x+3y=-4$$ Find the x-intercept: $\frac{1}{2}x+3(0)=-4\\ \frac{1}{2}x=-4\\ x=-8 $ Find the y-intercept: $\frac{1}{2}(0)+3y=-4\\ 3y=-4\\ y=-\frac{4}{3}$ Find another point: $x=-1\rightarrow y= -\frac{7}{6}\\x=1 \rightarrow y=-\frac{9}{2}\\x=2\rightarrow y=-\frac{5}{3}$
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