Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 21


See below

Work Step by Step

Given $$\frac{x^2}{36}+\frac{y^2}{4}=1$$ Rewrite as: $\frac{x^2}{6^2}+\frac{y^2}{2^2}=1$ Thus, we have $a=6\\b=2$
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